问题

混合3节点全闪存NX-3360-G5和4节点混合NX-1465-G5

  • 2019年2月11日
  • 4回复
  • 1504观点
j
徽章 +6
有可能混合，


3节点所有闪存NX-3360-G5＆

4节点杂交种NX-1465-G5

并形成AHV集群？

NX-3360-G5是2 * 10核心CPU，12 * 32GB内存，18 * 1.9TB SSD，而
NX-1465-G5为2 * 10核心CPU，8 * 32GB内存，1 * 960GB SSD，2 * 4TB HDD

存储撕裂如何在这种情况下工作？
    \r\n


    \r\n<\/h3>

    3 node All Flash<\/u><\/i> NX-3360-G5<\/b> &<\/h3>

    4 node Hybrid<\/u><\/i> NX-1465-G5<\/b><\/h3>and form a AHV cluster ?
    \r\n
    \r\nNX-3360-G5 is 2*10 core CPU, 12*32GB Memory, 18*1.9TB SSD whereas
    \r\nNX-1465-G5 is 2*10 core CPU, 8*32GB Memory, 1*960GB SSD, 2*4TB HDD
    \r\n
    \r\nhow storage tearing will work in this scenario ?","quoteUsername":"jitendra","translations":{"Common":{"like":"Like","unlike":"Unlike"},"Forum":{"Quote":"Quote","Share":"Share"}}}">

    4回复

    RichardsonPorto.
    秩
    UserLevel 3.
    徽章 +5
    是的，即，您可以找到以下文档的产品混合限制：https://portal.nutanix.com/#/page/docs/details?targetid=hardware-admin-ref-aos-v510:har- 混合混合限制-R.HTML

    如果满足以下条件，则可以在同一群集中混合All-SSD节点和混合SSD / HDD节点：
    • 混合All-Flash / Hybrid集群中需要至少两个ALL-SSD节点。
    • 每个节点类型（All-SSD /混合）的最小数量必须等于群集冗余因子。例如，冗余因子为2的群集必须具有至少2个混合和2个全SSD节点。
    • 只要群集包含两个或多个All-SSD节点，您就可以在包含混合节点的群集中的All-SSD节点上运行Guest虚拟机VM。
    Richardson Porto - LinkedIn：http：//linkedin.com/in/richardsonporto
    \r\n
    \r\n
    All-SSD nodes and hybrid SSD\/HDD nodes can be mixed in the same cluster if the following conditions are met:
      \r\n
    • A minimum of two all-SSD nodes are required in mixed all-flash\/hybrid clusters.<\/b> \r\n
    • The minimum number of each node type (all-SSD\/hybrid) must be equal to the cluster redundancy factor. For example, clusters with a redundancy factor of 2 must have a minimum of 2 hybrid and 2 all-SSD nodes.<\/b> \r\n
    • You can run guest VMs on the all-SSD nodes in clusters that also have hybrid nodes, as long as the cluster includes two or more all-SSD nodes.<\/b> \r\n<\/ul><\/blockquote>","quoteUsername":"RichardsonPorto","translations":{"Common":{"like":"Like","unlike":"Unlike"},"Forum":{"Quote":"Quote","Share":"Share"}}}">
    j
    徽章 +6
    嘿，谢谢Richardson。

    我还想知道，考虑两个块的硬件规范，我的总可用存储容量将是什么。

    在推荐DesignBrewz时，我正在附加结果存储效率为2：1和作为标准的故障转移计划（n + 1）但与驻留在SSD和HDD上的数据混淆。


    \r\n
    \r\nI would also like to know, what will be my total usable storage capacity considering hardware specs of both blocks.
    \r\n
    \r\nI am getting attached results while referring DesignBrewz with Storage Efficiency as 2:1 and Failover Plan as Standard (N+1)<\/u> but confused with data residing on SSDs and HDDs.
    \r\n
    \r\n
    \r\n

    <\/a><\/p>","quoteUsername":"jitendra","translations":{"Common":{"like":"Like","unlike":"Unlike"},"Forum":{"Quote":"Quote","Share":"Share"}}}">

    RichardsonPorto.
    秩
    UserLevel 3.
    徽章 +5
    总可用容量（容忍1节点故障）将是62.27TB，其中您将拥有30.92TB的SSD，10.59TB，由于数据减少而节省的70.76TB。
    Richardson Porto - LinkedIn：http：//linkedin.com/in/richardsonporto
    j
    徽章 +6
    谢谢Richardson。

    在这种情况下，我想知道热和寒冷的层。当我们有一个af块和一个混合块时。数据如何居住。
    \r\n
    \r\nI wonder how hot and cold tiers would work in this case. As we have one AF block and one Hybrid block. How data will reside.","quoteUsername":"jitendra","translations":{"Common":{"like":"Like","unlike":"Unlike"},"Forum":{"Quote":"Quote","Share":"Share"}}}">

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