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当群集为RF2时，当一个节点失败时，需要了解可用存储

  • 2021年9月23日
  • 1回复
  • 238意见
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  1. 你好，

    我有一个配置RF 2的3节点群集。当所有节点启动并运行时，我可以在Prism元素上看到以下的总群集资源。
  • CPU -388 GHz
  • RAM -4.5 TB（每个节点1.5 TB）
  • 存储-32.9 TB

假设如果1个节点失败，我的可用存储尺寸会减少吗？请帮我。

  1. 另外，我不明白一件事，我总共有42个SSD为1.92 TB = 80.64 TB，但实际上，使用RF2，我为什么只得到32.9 TB（没有任何数据效率选项）。理想情况下，我应该获得40 TB的可用空间。我检查了存储Sizer门户，并说我应该得到63 TB。请指导家伙，我想念什么。

图标

最好的答案Mikkisse2021年9月23日，15:36

Hello!<\/p>

I think this article can answer to all your questions:<\/p>

Recommended guidelines for maximum storage utilization on a cluster<\/a><\/p>

Also you operating with TB (Terabytes), but Nutanix shows you data in TiB (Tebibyte). Here is a calculator -\u00a0https:\/\/www.gbmb.org\/tb-to-tib<\/a><\/p>

Also check 1st and 2nd disks on your nodes, it should be less than other similar disks\u00a0in size, because part of it used for CVM needs. (Hardware - Diagram)<\/p>

\u00a0<\/p>

In your case you should not use more that 20TiB of storage in RF2, then you can tolerate to one node failure situation.\u00a0<\/p>

Sum of all your disks capacity on one node\u00a0= physical node capacity;<\/p>

Sum of all your nodes = physical capacity of your cluster;<\/p>

logical capacity = physical \/ 2 in your case;<\/p>

resilient capacity = (logical capacity - one node logical size) * 0,95. (this is my assumption).<\/p>","className":"post__content__best_answer"}">

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  • Hello,

    \tI have a 3 node cluster with RF 2 configured. When All the nodes are up and running I can see Total Cluster resources as below on the Prism Element.<\/li><\/ol>
    • CPU - 388 Ghz<\/li>\t
    • RAM - 4.5 TB ( 1.5 TB Per Node)<\/li>\t
    • Storage - 32.9 TB\u00a0<\/li><\/ul>

      \u00a0<\/p>

      Let\u2019s say If 1 node fails, Will my Available Storage size reduce? Please Help me.<\/p>

      \u00a0<\/p>

      1. Also, I don\u2019t understand one thing, I have Total 42 SSD of 1.92 TB = 80.64 TB, But in reality with RF2 why am I getting only 32.9 TB (without any data efficiency options enabled). I should Ideally get 40 TB of usable space. I checked on the storage sizer portal and it said I should get 63 TB. Please guide guys, what am I missing.\t
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    1回复

    Mikkisse
    UserLevel 3
    徽章 +2

    你好！

    我认为本文可以回答您的所有问题：

    推荐的指南，用于在集群上最大的存储利用

    您还使用TB（TBYTES）操作，但Nutanix在TIB（Tebibyte）中显示您的数据。这是一个计算器 -https://www.gbmb.org/tb-to-tib

    还要在节点上检查第一和第二个磁盘，它应该比其他大小的其他类似磁盘要小，因为其中一部分用于CVM需求。（硬件 - 图）

    在您的情况下，您不应使用RF2中的20TIB存储空间，然后可以忍受一个节点故障情况。

    一个节点上的所有磁盘容量的总和=物理节点容量；

    所有节点的总和=群集的物理容量；

    逻辑容量=物理 / 2在您的情况下；

    弹性容量=（逻辑容量 - 一个节点逻辑大小） * 0,95。（这是我的假设）。

    Hello!<\/p>

    I think this article can answer to all your questions:<\/p>

    Recommended guidelines for maximum storage utilization on a cluster<\/a><\/p>

    Also you operating with TB (Terabytes), but Nutanix shows you data in TiB (Tebibyte). Here is a calculator -\u00a0https:\/\/www.gbmb.org\/tb-to-tib<\/a><\/p>

    Also check 1st and 2nd disks on your nodes, it should be less than other similar disks\u00a0in size, because part of it used for CVM needs. (Hardware - Diagram)<\/p>

    \u00a0<\/p>

    In your case you should not use more that 20TiB of storage in RF2, then you can tolerate to one node failure situation.\u00a0<\/p>

    Sum of all your disks capacity on one node\u00a0= physical node capacity;<\/p>

    Sum of all your nodes = physical capacity of your cluster;<\/p>

    logical capacity = physical \/ 2 in your case;<\/p>

    resilient capacity = (logical capacity - one node logical size) * 0,95. (this is my assumption).<\/p>","quoteUsername":"mikkisse","translations":{"Common":{"like":"Like","unlike":"Unlike"},"Forum":{"Quote":"Quote","Share":"Share"}}}">

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